9.Diketahui fungsi f(x)=
[tex] \frac{x + 2}{3} [/tex]
jika bayangan m adalh 2 nilai m adalah![]()
[tex] \frac{x + 2}{3} [/tex]
jika bayangan m adalh 2 nilai m adalah
[tex]f(x) = \frac{x + 2}{3} [/tex]
[tex]y = \frac{x + 2}{3} [/tex]
[tex]x = \frac{y + 2}{3} [/tex]
[tex] \frac{y + 2}{3} = x[/tex]
[tex]y + 2 = 3x[/tex]
[tex]y = 3x - 2[/tex]
[tex]f {}^{ - 1} (x) =3x - 2[/tex]
[answer.2.content]![Matematika (+50) KuMat - Kuis Matematika<br />
Materi: Logaritma<br /><br />
Diketahui:<br />
[tex]\large\text{$\begin{aligned}&{}^{\sf2}\log\left({}^{\sf8}\log x\right)={}^{\sf8}\log\left({}^{\sf2}\log x\right)\end{aligned}$}[/tex]<br /><br />
Pertanyaan:<br />
[tex]\Large\text{$\begin{aligned}&\left({}^{2}\log{x}\right)^2=.....?\end{aligned}$}[/tex]](https://1.bp.blogspot.com/-FxxoZkxtk_U/WKAvV2Gd6iI/AAAAAAAACd0/UTrLC-1x23k1E0oqRLErM2XliW2XDiBlQCK4B/s1600/dif.jpg "Matematika (+50) KuMat - Kuis Matematika<br />
Materi: Logaritma<br /><br />
Diketahui:<br />
[tex]\large\text{$\begin{aligned}&{}^{\sf2}\log\left({}^{\sf8}\log x\right)={}^{\sf8}\log\left({}^{\sf2}\log x\right)\end{aligned}$}[/tex]<br /><br />
Pertanyaan:<br />
[tex]\Large\text{$\begin{aligned}&\left({}^{2}\log{x}\right)^2=.....?\end{aligned}$}[/tex]")
