a pangkat 5 b pangkat negatif 2 per a pangkat 4 b pangkat 7 di kali a pangkat 2 b pangkat 3 per a b pangkat negatif 4
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Penjelasan dengan langkah-langkah:
= a⁵b-²/a⁴b⁷ × a²b³/ab-⁴
= a⁵-⁴. b-²-⁷ × a²-¹. b³--⁴
= a¹. b-²+-⁷ × a¹. b³+⁴
= a. b-⁹. a¹. b⁷
= a¹+¹. b-⁹+⁷
= a². b-²
= a²/b²
[answer.2.content]![Matematika (+50) KuMat - Kuis Matematika<br />
Materi: Logaritma<br /><br />
Diketahui:<br />
[tex]\large\text{$\begin{aligned}&{}^{\sf2}\log\left({}^{\sf8}\log x\right)={}^{\sf8}\log\left({}^{\sf2}\log x\right)\end{aligned}$}[/tex]<br /><br />
Pertanyaan:<br />
[tex]\Large\text{$\begin{aligned}&\left({}^{2}\log{x}\right)^2=.....?\end{aligned}$}[/tex]](https://1.bp.blogspot.com/-FxxoZkxtk_U/WKAvV2Gd6iI/AAAAAAAACd0/UTrLC-1x23k1E0oqRLErM2XliW2XDiBlQCK4B/s1600/dif.jpg "Matematika (+50) KuMat - Kuis Matematika<br />
Materi: Logaritma<br /><br />
Diketahui:<br />
[tex]\large\text{$\begin{aligned}&{}^{\sf2}\log\left({}^{\sf8}\log x\right)={}^{\sf8}\log\left({}^{\sf2}\log x\right)\end{aligned}$}[/tex]<br /><br />
Pertanyaan:<br />
[tex]\Large\text{$\begin{aligned}&\left({}^{2}\log{x}\right)^2=.....?\end{aligned}$}[/tex]")
